FANDOM


20 May 2015
Item Base date Base price Price on adjustment date Comments
Lobster 25 January 2008 175 196 Unchanged
Bass 195 225
Tuna 81 163
Swordfish 272 295
Monkfish 233 336
Shark 657 739
Cake 52 91
Chocolate cake 150 421
Ugthanki kebab 887 810 Removed item
Kebab 32 276
Sea turtle 1,264 2,690
Manta ray 1,794 1,907
Sweetcorn 135 43
Roast bird meat 22 19
Admiral pie 1,031 497
Wild pie 3,491 985
Redberry pie 381 1,280
Garden pie 657 475
Stew 100 1,102
Bread 433 Added item
Strawberries (5) 318
Saradomin brew (4) 9,762
Salmon 80
Cavefish 1,256
Rocktail 1,814
Great white shark 912

Calculations

From the old divisor obtained from the templates:

{div}_{\text{old}} = 19.0000


We need to calculate a new divisor:

{div}_{\text{new}} = {div}_{\text{old}} \times \frac{\sum \left ( \frac{p}{q} \right )_{\text{new}}}{\sum \left ( \frac{p}{q} \right )_{\text{old}}}


To calculate the new divisor, we need to find:

\begin{align}

  \sum \left ( \frac{p}{q} \right )_{\text{old}} & = \text{sum of ratios prior to change} \\

    & = \text{sum of unchanged ratios} + \text{sum of removed ratios} \\

    & = \left (\frac{196}{175} + \frac{225}{195} + \dots + \frac{421}{150} \right ) + \left (\frac{810}{887} + \frac{276}{32} + \dots + \frac{1,102}{100} \right ) \\

    & = 42.27255853 \text{ (up to 8 d.p.)}

  \end{align}


And also:

\begin{align}

  \sum \left ( \frac{p}{q} \right )_{\text{new}} & = \text{sum of ratios prior to change} - \text{sum of removed ratios} + \text{sum of added ratios} \\

    & = \sum \left ( \frac{p}{q} \right )_{\text{old}} - \text{sum of removed ratios} + \text{number of added items} \\

    & = 42.27255853 - \left ( \frac{810}{887} + \frac{276}{32} + \dots + \frac{1,102}{100} \right ) + 7 \\

    & = 19.49428715 \text{ (up to 8 d.p.)}

  \end{align}


Thus, the new divisor is:

\begin{align}

  {div}_{\text{new}} & = {div}_{\text{old}} \times \frac{\sum \left ( \frac{p}{q} \right )_{\text{new}}}{\sum \left ( \frac{p}{q} \right )_{\text{old}}} \\

    & = 19.0000 \times \frac{42.27255853}{19.49428715} \\

    & = 8.7619 \text{ (4 d.p.)}

  \end{align}

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